Class WordResolver


  • public final class WordResolver
    extends Object
    A specialized Map/Symbol table - like data structure that can be used for both checking whether a word (passed in as a char array) exists in certain set of words AND getting that word as a String. It is reasonably efficient both time and speed-wise, at least for certain use cases; specifically, if there is no existing key to use, it is more efficient way to get to a shared copy of that String The general usage pattern is expected to be such that most checks are positive, ie. that the word indeed is contained in the structure.

    Although this is an efficient data struct for specific set of usage patterns, one restriction is that the full set of words to include has to be known before constructing the instnace. Also, the size of the set is limited to total word content of about 20k characters.

    TODO: Should document the internal data structure...

    • Field Detail

      • MAX_WORDS

        public static final int MAX_WORDS
        Maximum number of words (Strings) an instance can contain
        See Also:
        Constant Field Values
    • Method Detail

      • constructInstance

        public static WordResolver constructInstance​(TreeSet<String> wordSet)
        Tries to construct an instance given ordered set of words.

        Note: currently maximum number of words that can be contained is limited to MAX_WORDS; additionally, maximum length of all such words can not exceed roughly 28000 characters.

        Returns:
        WordResolver constructed for given set of words, if the word set size is not too big; null to indicate "too big" instance.
      • size

        public int size()
        Returns:
        Number of words contained
      • find

        public String find​(char[] str,
                           int start,
                           int end)
        Parameters:
        str - Character array that contains the word to find
        start - Index of the first character of the word
        end - Index following the last character of the word, so that end - start equals word length (similar to the way String.substring() has).
        Returns:
        (Shared) string instance of the word, if it exists in the word set; null if not.
      • find

        public String find​(String str)
        Returns:
        (Shared) string instance of the word, if it exists in the word set; null if not.